Ravindra Jadeja bowled dangerously in the second Test against Australia in Delhi. The left-arm spinner, who took three wickets in the first innings, took seven wickets in the second innings. Jadeja took six wickets on the third day of the match on Sunday (February 19). Earlier on Saturday, he dismissed Usman Khawaja. In this way, he took a total of seven wickets in the second innings. The funny thing is that Jadeja clean bowled five out of seven batsmen.

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For the first time in the last 21 years, this has happened in Tests when a bowler has clean bowled five batsmen in an innings. Last time Shoaib Akhtar did this. He clean bowled five batsmen against New Zealand in 2002 at the Gaddafi Stadium in Lahore. If we talk about spin bowler, then in 1992 Anil Kumble did this last time. He achieved this feat against South Africa in Johannesburg.

Jadeja Left Five Players Behind in this Matter

Jadeja has taken 259 wickets in Tests. He has played 62 matches so far. In terms of taking the most Test wickets, he has equaled former Australian fast bowler Jason Gillespie and Joel Garner of the West Indies. Garner took 259 wickets in 58 Tests and Gillespie took 259 wickets in 71 Tests. In this match, Jadeja left behind five bowlers simultaneously. He left behind West Indies’ Michael Holding (249 wickets), England’s Brian Statham (252), New Zealand’s Neil Wagner (253), West Indies’ Kemar Roach (254) and England’s Graeme Swann (255).

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What Happened in the Match?

Australia scored 263 runs in the first innings. At the same time, the Indian team managed to score 262 runs. Australia got a one run lead in the first innings. His team was reduced to 113 runs in the second innings. In this way India got the target of 115 runs. In the second innings for Australia, Travis Head scored 43 and Marnus Labuschagne scored 35 runs. Apart from these two, no batsman could touch the double figure. Veteran batsman Steve Smith could only score nine runs. Apart from Jadeja’s seven wickets for India, Ravichandran Ashwin took three wickets.