During the Delhi Test match against Australia, in the second innings, Indian Cricket Team captain Rohit Sharma sacrificed his wicket to save Cheteshwar Pujara. Rohit Sharma was batting tremendously but there was a blunder between him and Pujara during running and after that Rohit Sharma lost his wicket. This was Pujara’s 100th Test match and for this reason Rohit Sharma himself thought it better to get out to save him.

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In the Delhi Test Match, the Australian Team Was Reduced to Just 113 Runs in their Second Innings

In the Delhi Test match, the Australian team was reduced to just 113 runs in their second innings. Playing ahead of yesterday’s score, the Kangaroo team lost their 9 wickets very quickly. Ravindra Jadeja took seven wickets for just 42 runs. He also took 3 wickets in the first innings and in this way Jadeja took 10 wickets in total.

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The start of the Indian team chasing the target was not good and they got the first blow in the form of KL Rahul only on the score of 6 runs. KL Rahul got out after scoring just one run. After his return to the pavilion, Rohit Sharma and Pujara handled the innings. During this, Captain Rohit Sharma was seen in a very aggressive mood. He scored 31 runs in just 20 balls and during this he hit 3 fours and 2 sixes.

Rohit Sharma Lost his Wicket in the Second Run

However, in the seventh over of the innings, he lost his wicket in the process of taking two runs. There was a slight misunderstanding between Pujara and him. Rohit Sharma went back to his crease after seeing the fielder but by then Pujara had reached towards him and Rohit came out of the crease to save him and lost his wicket. You also watch this video.